SOLUTION: lowest terms 64u^3/112u^7

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Question 482047: lowest terms
64u^3/112u^7
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

64u%5E3%2F112u%5E7...simplify..divide both 64 and 112 by 16
cross%2864%294u%5E3%2Fcross%28112%297u%5E7

4u%5E3%2F7u%5E7....now apply exponent rule a%5Em%2Fa%5En=a%5Em-n%29%0D%0A%0D%0A%0D%0A%7B%7B%7B4u%5E%283-7%29

4u%5E%28-4%29

4%2F7u%5E4