SOLUTION: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer.
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-> SOLUTION: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer.
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Question 482001: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer. Found 2 solutions by MathLover1, josmiceli:Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!
You can always write these out the long way
( if the numbers aren't very big ) and look at them
The main thing to notice is that there are an odd number of
(-2)'s and an even number of (-5)'s
Think of the (-2)'s grouped in pairs with one left over
(-2)*(-2) this is positive
(-2)*(-2) also positive
(-2) this is negative
So, you have (+) x (+) x (-) = (-)
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What if it was ?
You would pair these up the same way, so you'd have
a bunch of (+) x (+) x (+) . . . etc and one (-) left. that would
give you a minus result
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Back to your problem, then
and
OK?
