SOLUTION: Please help me analyze this problem. I tried C= 10!/8(10-8) = 10*9/2= 45. Is this correct? A student must answer eight of ten questions on an exam. How many different choices ca

Algebra ->  Probability-and-statistics -> SOLUTION: Please help me analyze this problem. I tried C= 10!/8(10-8) = 10*9/2= 45. Is this correct? A student must answer eight of ten questions on an exam. How many different choices ca      Log On


   

Question 48195: Please help me analyze this problem. I tried C= 10!/8(10-8) = 10*9/2= 45. Is this correct?
A student must answer eight of ten questions on an exam. How many different choices can a student make?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Yes.
And did you notice that 10C8 = 10C2?
Cheers,
Stan H.