SOLUTION: Rewrite the expression as a single logarithm: ln(a + b) + ln(a - b) - 2 ln c Thank you very much!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Rewrite the expression as a single logarithm: ln(a + b) + ln(a - b) - 2 ln c Thank you very much!      Log On


   

Question 48194This question is from textbook College Algebra
: Rewrite the expression as a single logarithm:
ln(a + b) + ln(a - b) - 2 ln c
Thank you very much! This question is from textbook College Algebra

Answer by atif.muhammad(135) About Me  (Show Source):
You can put this solution on YOUR website!
ln%28a+%2B+b%29+%2B+ln%28a+-+b%29+-+2+ln+c


Use logarithmic law: log a + log b = log ab



Use logarithmic law: a log b = log (b^a)

ln+%28a%5E2-b%5E2%29+-+2+ln+c

ln+%28a%5E2-b%5E2%29+-+ln+%28c%5E2%29

Use logarithmic law: log a - log b = log %28a%2Fb%29

ln+%28a%5E2-b%5E2%29+-+ln+%28c%5E2%29

ln+%28%28a%5E2-b%5E2%29%2F%28c%5E2%29%29