SOLUTION: If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 481640: If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution?
------------------------------------------
Equation:
acid + acid = acid
0.35*70 + 0*x = 0.25(70+x)
----
Multiply thru by 100 to get:
35*70 + 0 = 25*70+25x
-----
25x = 10*70
----
x = 28mL (amt. of water needed)
=======================
Cheers,
Stan H.