SOLUTION: Find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^=-12x

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^=-12x      Log On


   

Question 481498: Find the focus and directrix of the parabola with the given equation. Then graph the parabola.
y^=-12x
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the focus and directrix of the parabola with the given equation. Then graph the parabola.
y^=-12x
**
y^2=-12x
This is an equation of a parabola with a horizontal axis of symmetry.
Its standard form: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex.
For given equation:
Vertex(0,0)
4p=12
p=3
Focus:(-3,0)
Directrix: x=3
see the graph below as a visual check on the answers:
..
y=±(-12x)^.5
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+%28-12x%29%5E.5%2C-%28-12x%29%5E.5%29+