SOLUTION: Answer the following: (A) Find the binomial probability P(x = 5), where n = 14 and p = 0.70. (B) Set up, without solving, the binomial probability P(x is at most 5) using probabi

Algebra ->  Probability-and-statistics -> SOLUTION: Answer the following: (A) Find the binomial probability P(x = 5), where n = 14 and p = 0.70. (B) Set up, without solving, the binomial probability P(x is at most 5) using probabi      Log On


   



Question 481453: Answer the following:
(A) Find the binomial probability P(x = 5), where n = 14 and p = 0.70.
(B) Set up, without solving, the binomial probability P(x is at most 5) using probability notation.
(C) How would you find the normal approximation to the binomial probability P(x = 5) in part A? Please show how you would calculate µ and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations
Thanks

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Answer the following:
(A) Find the binomial probability P(x = 5), where n = 14 and p = 0.70.
Ans: 14C5(0.7)^5(0.3)^9 = binompdf(14,0.7,5) = 0.00660.7746
------------------------------
(B) Set up, without solving, the binomial probability P(x is at most 5) using probability notation.
P(0<= x <=5) = 14C0(0.7)^0*(0.3)^14+14C1(0.7)*(0.3)^13+ etc.
-------------------------
(C) How would you find the normal approximation to the binomial probability P(x = 5) in part A?
Please show how you would calculate µ and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations
u = np = 14*0.7 = 2
s = sqrt(npq) = sqrt(2*0.3) = 0.7746
---------------
binomial probability (x = 5)
equals normal approximation probability (4.5 < x < 5.5)
============
Cheers,
Stan H.
===========