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Question 481381: Identify the center and the radius of the circle (x – 4)2 + (y + 3)2 = 81.
and
Identify the center of the ellipse x^2/3+(y+1)^2/5=1
thank you!
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Identify the center and the radius of the circle (x – 4)2 + (y + 3)2 = 81.
and Identify the center of the ellipse x^2/3+(y+1)^2/5=1.
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Standard form for equation of a circle: (x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates
of the center.
For given equation of circle:
(x–4)^2+(y+3)^2=81
center: (4,-3)
radius: √81=9
..
Standard form for equation of an ellipse with vertical major axis:
(x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k) being the (x,y) coordinates of the center.
For given equation of ellipse:
x^2/3+(y+1)^2/5=1
center: (0,-1)
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