SOLUTION: 1- Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at
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Question 481275: 1- Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches the first from the time the second cyclist started biking?
2- Jim can fill a pool carrying buckets of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
3- John is travelling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! 1- Two cyclists start biking from a trail’s start 3 hours apart.
The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour.
How much time will pass before the second cyclist catches the first from the time the second cyclist started biking?
:
Let t = travel time of the 2nd cyclist when they meet
then
(t+3) = travel time of the 1st cyclist
:
When they meet, they will have traveled the same dist, write a dist equation: d=speed*time
:
10t = 6(t + 3)
solve for t
:
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2- Jim can fill a pool carrying buckets of water in 30 minutes.
Sue can do the same job in 45 minutes.
Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
:
Change Tony's time to 90 min
Let t = time required when working together
let the completed job = 1 (a full pool)
Each will do a fraction of the job, the three fractions add up to 1
: + + = 1
Multiply thru by 90 to clear the denominators, find t
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3- John is traveling to a meeting that is 28 miles away.
He needs to be there in 30 minutes.
How fast does he need to go to make it to the meeting on time?
:
Change 30 min to .5 hrs
speed = dist/time
s =
