SOLUTION: Question: "Each side of a square is 4 m long. When each side is increased by x m, the area is doubled. Find the value of x." Please help!!!

Algebra ->  Surface-area -> SOLUTION: Question: "Each side of a square is 4 m long. When each side is increased by x m, the area is doubled. Find the value of x." Please help!!!      Log On


   

Question 481007: Question: "Each side of a square is 4 m long. When each side is increased by x m, the area is doubled. Find the value of x." Please help!!!
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
4*4 = 16 sq meters
2*16 = 32 sq meters
-----------
s%5E2+=+32
x = s - 4 meters
What's the big deal?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Each side of a square is 4 m long, therefore A = 16m^2

When each side is increased by x, then (4+x)(4+x) = 32m^2

 (4+x)(4+x) = 32m^2

  16 + 8x + x^2 = 32

  x^2 + 8x - 16 = 0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 

x+=+%28-8+%2B-+sqrt%28+128%29%29%2F%282%29+ 

tossing out negative solution for number of meters

 x = 1.6569m



CHECKING our Answer***

  5.6569*5.6569 = 32m^2