SOLUTION: how do i solve log2x 16=-2. i cant solve it b/c of the negative. plz help me =[

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: how do i solve log2x 16=-2. i cant solve it b/c of the negative. plz help me =[      Log On


   

Question 48096: how do i solve log2x 16=-2. i cant solve it b/c of the negative. plz help me =[
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
log%282x%2C16%29+=+-2
16+=+%282x%29%5E%28-2%29
16+=+1%2F%284x%5E2%29
1%2F16+=+4x%5E2
1%2F64+=+x%5E2
+-1%2F8+=+x
'b' can not be negative so your solution is: 1%2F8+=+x