SOLUTION: the sum of two number is 3 and the sum of their squares is 12, find their product

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Question 480846: the sum of two number is 3 and the sum of their squares is 12, find their product
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

the sum of two number is 3

Let x and (3-x) represent the numbers

Question states***

 x^2 + (3-x)^2 = 12

 x^2 + 9 -6x + x^2 = 12

 2x^2 - 6x -3 = 0

 x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 

 x+=+%286+%2B-+sqrt%2860%29%29%2F%284%29+ 

product of these numbers:

 %286+%2Bsqrt%2860%29%29%286-+sqrt%2860%29%29%2F16+ 

  (36 -60)/16 = -24/16 = -3/2