SOLUTION: If v,w,x,y, and z are positive consecutive integers whose sum is 0, then what is the value of Z+V/Y-V? A)3 B)2 C)4/3 D)6/5 E)-2

Algebra ->  Sequences-and-series -> SOLUTION: If v,w,x,y, and z are positive consecutive integers whose sum is 0, then what is the value of Z+V/Y-V? A)3 B)2 C)4/3 D)6/5 E)-2      Log On


   



Question 480756: If v,w,x,y, and z are positive consecutive integers whose sum is 0, then what is the value of Z+V/Y-V?
A)3 B)2 C)4/3 D)6/5 E)-2

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
If v,w,x,y, and z are positive consecutive integers whose sum is 0, then what is the value of z+v/y-v?
It's impossible to have any POSITIVE numbers whose sum is 0, so 
I will assume you didn't mean "positive", otherwise there is no 
solution.  So I'll delete the word "positive" and assume you meant
this:

If v,w,x,y, and z are consecutive positive integers whose sum is 0, then what is the value of z+v/y-v?
You didn't put any parentheses in to show where numerators and 
denominators begin and end, so I can't tell whether you mean

this:

z%2Bv%2Fy-v, 

or this,

z+%2B+v%2F%28y-v%29, 

or this:

%28z%2Bv%29%2F%28y-v%29


The only 5 consecutive integers that have sum 0 are -2,-1,0,1,2, so

v=-2, w=-1, x=0, y=1, z = 2

If you meant this:

z%2Bv%2Fy-v, then it's 2%2B%28-2%29%2F1-%28-2%29+=+2-2%2B2=2  

If you meant this:

z+%2B+v%2F%28y-v%29, then it's 2+%2B+%28-2%29%2F%281-%28-2%29%29=+2%2B+%28-2%29%2F%281%2B2%29=+2-2%2F3=6%2F3-2%2F3=4%2F3%29  

If you meant this:

%28z%2Bv%29%2F%28y-v%29, then it's %282%2B%28-2%29%29%2F%281-%28-2%29%29=+%282-2%29%2F%281%2B2%29=0%2F3=0.

You have to let us know using parentheses where numerators and
denominators start and end. 

Edwin