SOLUTION: 20x^2+13x+2 Please help factor.

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Question 480752: 20x^2+13x+2

Please help factor.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 20x%5E2%2B13x%2B2, we can see that the first coefficient is 20, the second coefficient is 13, and the last term is 2.



Now multiply the first coefficient 20 by the last term 2 to get %2820%29%282%29=40.



Now the question is: what two whole numbers multiply to 40 (the previous product) and add to the second coefficient 13?



To find these two numbers, we need to list all of the factors of 40 (the previous product).



Factors of 40:

1,2,4,5,8,10,20,40

-1,-2,-4,-5,-8,-10,-20,-40



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 40.

1*40 = 40
2*20 = 40
4*10 = 40
5*8 = 40
(-1)*(-40) = 40
(-2)*(-20) = 40
(-4)*(-10) = 40
(-5)*(-8) = 40


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 13:



First NumberSecond NumberSum
1401+40=41
2202+20=22
4104+10=14
585+8=13
-1-40-1+(-40)=-41
-2-20-2+(-20)=-22
-4-10-4+(-10)=-14
-5-8-5+(-8)=-13




From the table, we can see that the two numbers 5 and 8 add to 13 (the middle coefficient).



So the two numbers 5 and 8 both multiply to 40 and add to 13



Now replace the middle term 13x with 5x%2B8x. Remember, 5 and 8 add to 13. So this shows us that 5x%2B8x=13x.



20x%5E2%2Bhighlight%285x%2B8x%29%2B2 Replace the second term 13x with 5x%2B8x.



%2820x%5E2%2B5x%29%2B%288x%2B2%29 Group the terms into two pairs.



5x%284x%2B1%29%2B%288x%2B2%29 Factor out the GCF 5x from the first group.



5x%284x%2B1%29%2B2%284x%2B1%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%285x%2B2%29%284x%2B1%29 Combine like terms. Or factor out the common term 4x%2B1



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Answer:



So 20%2Ax%5E2%2B13%2Ax%2B2 factors to %285x%2B2%29%284x%2B1%29.



In other words, 20%2Ax%5E2%2B13%2Ax%2B2=%285x%2B2%29%284x%2B1%29.



Note: you can check the answer by expanding %285x%2B2%29%284x%2B1%29 to get 20%2Ax%5E2%2B13%2Ax%2B2 or by graphing the original expression and the answer (the two graphs should be identical).