SOLUTION: solve Log(a)(7x+1)= Log(a)(4x+16)
where both sides are multiplied by Log(a) can't i really just ignore that and
solve the equation 7x+1=4x+16
which reduces to 3x=15 so x=5?
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-> SOLUTION: solve Log(a)(7x+1)= Log(a)(4x+16)
where both sides are multiplied by Log(a) can't i really just ignore that and
solve the equation 7x+1=4x+16
which reduces to 3x=15 so x=5?
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Question 48065: solve Log(a)(7x+1)= Log(a)(4x+16)
where both sides are multiplied by Log(a) can't i really just ignore that and
solve the equation 7x+1=4x+16
which reduces to 3x=15 so x=5? Answer by atif.muhammad(135) (Show Source):