SOLUTION: Abraham Read the Book component of 480 pages in a certain period by reading the same number of pages per day. But he was able to finish reading the book before 5 days from the same
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Question 480481: Abraham Read the Book component of 480 pages in a certain period by reading the same number of pages per day. But he was able to finish reading the book before 5 days from the same period if the 16-page read more on a daily basis. How was completed by the specified period in which Abraham read the book?? Answer by mathstutor494(120) (Show Source):
You can put this solution on YOUR website! Let Abraham reading speed be x pages per day
So time taken to read 480 pages = 480/x days
No of days required to read 480 pages when 16-page read more on a daily basis= 480/(x+16)
Further it is given that he was able to finish reading the book before 5 days from the same period, hence
(480/x)- {480/(x+16)} = 5
Simplifying above eqn leads to
x^2+16x-1536=0
x^2+48x-32x-1536=0
x(x+48)-32(x+48)=0
(x+48)(x-32)=0
So x = 32 or -48
-48 is not a valid answer
So the correct answer is : reading speed was 32 pages per day which took 15 days to read 480 pages. After increasing speed by 16 pages new speed became 32+16 = 48 pages per day which took 480/48 = 10 days thus he was able to finish reading the book before 5 days from the same period.
