SOLUTION: Find the solution of the exponential equation,correct to 4 decimal places:
7^x/2 = 5^1-x
I got:
log 7^x/2 = log 5^1-x
x/2log7 = (1-x)log5
Thank you so much!
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Find the solution of the exponential equation,correct to 4 decimal places:
7^x/2 = 5^1-x
I got:
log 7^x/2 = log 5^1-x
x/2log7 = (1-x)log5
Thank you so much!
Log On
Question 48041This question is from textbook College Algebra
: Find the solution of the exponential equation,correct to 4 decimal places:
7^x/2 = 5^1-x
I got:
log 7^x/2 = log 5^1-x
x/2log7 = (1-x)log5
Thank you so much! This question is from textbook College Algebra
You can put this solution on YOUR website! I got:
log 7^x/2 = log 5^1-x
(x/2)log7 = (1-x)log5
Now you need to solve for "x", as follows:
x/(1-x)=(2)(log5/log7) =2(0.827...)=1.65
x=1.65-1.65x
2.65x=1.65
x=0.624...
Cheers,
Stan H.
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