Question 480122: find cot b and sin b of an angke whose equation of its terminal side is 5x + 2y = 0 where x>0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! ): find cot b and sin b of an angke whose equation of its terminal side is 5x + 2y = 0 where x>0
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Let x = 2, then y = -5
Let x = 0, then y = 0
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The terminal side passes thru (2,-5)
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Since x = 2 and y = -5,
r = sqrt[2^2 + 5^2] = sqrt[29]
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cot = x/r = 2/sqrt(29)
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sin = y/r = -5/sqrt(29)
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Cheers,
Stan H.
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