SOLUTION: bob has $2.90 in pennies nickels and dimes. he has the same number of pennies and nickels. if the number of dimes is 5 more than the number of nickels, how many of each type of co

Algebra ->  Expressions-with-variables -> SOLUTION: bob has $2.90 in pennies nickels and dimes. he has the same number of pennies and nickels. if the number of dimes is 5 more than the number of nickels, how many of each type of co      Log On


   

Question 480120: bob has $2.90 in pennies nickels and dimes. he has the same number of pennies and nickels. if the number of dimes is 5 more than the number of nickels, how many of each type of coin does he have?
Answer by lwsshak3(11628) About Me  (Show Source):
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bob has $2.90 in pennies nickels and dimes. he has the same number of pennies and nickels. if the number of dimes is 5 more than the number of nickels, how many of each type of coin does he have?
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let x=number of pennies and nickels
x+5 = number of dimes
.01x+.05x+.10(x+5)=2.90
.06x+.10x+.50=2.90
.16x=2.90-.50=2.40
.16x=2.40
x=2.40/.16=15
Ans:
15 pennies
15 nickels
20 dimes