Question 480091: Find the slope-intercept form, standard form and point slope form of the equation of the line
described
A line with y-intercept of (0, -3) and x-intercept of (-5, 0)
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the slope-intercept form, standard form and point slope form of the equation of the line
described
A line with y-intercept of (0, -3) and x-intercept of (-5, 0)
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If the y-int is (0,A) and the x-int is (B,0), the eqn is
Ax + By + AB = 0
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-3x - 5y + 15 = 0
3x + 5y = 15 standard form
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y = (-3/5)x + 3 slope-intercept form
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You can do it like this, too
Find the slope, m = diffy/diffx = 3/-5 = -3/5
Use y = mx + b and either point to find b (we'll pretend we don't know it)
-3 = (-3/5)*0 + b
b = -3
--> y = (-3/5)x - 3 slope-int form
3x + 5y = 15
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