Question 480082: Divide and check
(x^3+2x^2-3x+2)/(x+1)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Divide and check
(x^3+2x^2-3x+2)/(x+1)
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Using synthetic division:
-1)....1....2....-3....2
........1....1....-4..|..6
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Quotient: x^2+x-4
Remainder: 6
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Checking:
(x+1)(x^2+x-4)
= x^3+x^2-4x+x^2+x-4
= x^3+2x^2-3x-4 + 6
= x^3+2x^2-3x+2
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Cheers,
Stan H.
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