You can put this solution on YOUR website! What are the four missing terms between 4 and 1/16 in the geometric sequence?
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a(1) = 4
a(6) = 1/16
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a = 4
a(6) = 4*r^5 = 1/16
r^5 = 1/64
r = (1/64)^(1/5) = (2^(-6))^(1/5) = 2^(-6/5)
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2nd term: 4*2^(-6/5)
3rd term: 4*2^(-12/5)
4th term: 4*2^(-18/5)
5th term: 4*2^(-24/5)
6th term: 4*2^(-30/5) = 4*2^(-6) = 2^(-4) = 1/16
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Cheers,
Stan H.
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