You can put this solution on YOUR website! What is the sum of the first fourteen terms of the geometric series 1/3 + 1/12 + 1/49
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a = 1/3
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r = (1/12)/(1/3) = 1/4
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S(n) = a[1-r^n]/[1-r]
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S(14) = (1/3)[1-(1/4)^14]/[1-(1/4] = (1/3)[1/(3/4)] = (1/3)(4/3) = 4/9
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Cheers,
Stan H.