SOLUTION: Scores on an English placement test are normally distributed with a mean of 55 and standard deviation of 6.5. What score could be used to identify the top 5%?
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Question 479657: Scores on an English placement test are normally distributed with a mean of 55 and standard deviation of 6.5. What score could be used to identify the top 5%? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Scores on an English placement test are normally distributed with a mean of 55 and standard deviation of 6.5. What score could be used to identify the top 5%?
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Find the z-value with a right-tail of 5%
invNorm(0.95) = 1.645
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Find the corresponding test score using x = z*s+u
x = 1.645*6.5+55
x = 65.69..
cheers,
Stan H.
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