SOLUTION: I need help with this identity. Thank you 1+sec(theta)/sec(theta)=sin^2(theta)/1-cos(theta) I keep hitting a roadblock as I end up with 1+sec(theta)=1+cos(theta)(sec(theta)

Algebra ->  Trigonometry-basics -> SOLUTION: I need help with this identity. Thank you 1+sec(theta)/sec(theta)=sin^2(theta)/1-cos(theta) I keep hitting a roadblock as I end up with 1+sec(theta)=1+cos(theta)(sec(theta)      Log On


   

Question 479638: I need help with this identity. Thank you
1+sec(theta)/sec(theta)=sin^2(theta)/1-cos(theta)
I keep hitting a roadblock as I end up with 1+sec(theta)=1+cos(theta)(sec(theta)
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
=<=>
%281%2Bcos%28theta%29%29%281-cos%28theta%29%29=%28sin%28theta%29%29%5E2<=>
1-%28cos%28theta%29%29%5E2=%28sin%28theta%29%29%5E2<=>1=%28sin%28theta%29%29%5E2%2B%28cos%28theta%29%29%5E2
The final equality is an well known identity.