SOLUTION: (4^-1 + 2^-1)^2
I know that i have to apply the negative exponent property to each term, and then get a common denominator and add, but that is about all i can figure out.
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-> SOLUTION: (4^-1 + 2^-1)^2
I know that i have to apply the negative exponent property to each term, and then get a common denominator and add, but that is about all i can figure out.
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Question 479480: (4^-1 + 2^-1)^2
I know that i have to apply the negative exponent property to each term, and then get a common denominator and add, but that is about all i can figure out. Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (4^-1 + 2^-1)^2
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[(1/4) + (1/2)]^2
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[(2+4)/8]^2
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= (3/4)^2
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= 9/16
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Cheers,
Stan H.
(4-1 + 2-1)2
I'll do it different from the way the other tutor did it, just
to illustrate another method:
Let's wait till later to apply the negative exponent property:
Let's write 4 as 22
[(22)-1 + 2-1]2
(2-2 + 2-1)2
(2-2 + 2-1)(2-2 + 2-1)
Us FOIL and add exponents to multiply
2-4 + 2-3 + 2-3 + 2-2
Combine the middle two terms as 2 of them
2-4 + 2×2-3 + 2-2
Add exponents in the middle term
2-4 + 2-2 + 2-2
Now the middle and last terms can be combined as two of them:
2-4 + 2×2-2
Add exponents to simplify the second term:
2-4 + 2-1
Finally we apply the negative exponent property:
+ +
Get a LCD of 16
+ +
Edwin
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