SOLUTION: how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet

Algebra ->  Rectangles -> SOLUTION: how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet       Log On


   

Question 479470: how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how do you find the dimensions of a rectangle with the area of 120 square feet and a perimeter of 44 feet
----------------------
Equations:
LW = 120
44 = 2(L+W)
-----
22 = L+W
L = 22-W
----
Substitute for "L" and solve for "W":
(22-W)W = 120
22W-W^2 = 120
----
W^2-22W+120 = 0
----
Factor:
(W-10)(W-12) = 0
----
If W = 10, L = 12
If W = 12, L = 10
======================
Cheers,
stan H.