SOLUTION: the hypotenuse of an isosceles right triangle is 10sqrt of 2.find the lengths of the other sides?

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Question 479142: the hypotenuse of an isosceles right triangle is 10sqrt of 2.find the lengths of the other sides?
Found 2 solutions by Tatiana_Stebko, J2R2R:
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
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the Pythagorean theorem a%5E2%2Bb%5E2=c%5E2
c=10sqrt%282%29
The triangle is right and isosceles, so a=b
a%5E2%2Ba%5E2=%2810sqrt%282%29%29%5E2
2a%5E2=100%2A2
a%5E2=100
a=10
Answer 10 and 10

Answer by J2R2R(94) About Me  (Show Source):
You can put this solution on YOUR website!
If it is an isosceles right-angled triangle then the square on the hypotenuse equals twice the square of the other sides (which is the sum of the squares of the other two sides because they are equal).

(10 sqrt of 2) squared = 200 = twice the other sides squared.

Therefore the other sides squared = 100; giving the other sides are 10.

10 squared plus 10 squared = 200 = (10 sqrt 2) squared.