SOLUTION: in the diagram, right triangle ABC is inscribed in circle O, angle ACB is a right angle, line segment AB is a diameter, AC = 5 and BC = 12 whats the area of the shaded portion to t

Algebra ->  Volume -> SOLUTION: in the diagram, right triangle ABC is inscribed in circle O, angle ACB is a right angle, line segment AB is a diameter, AC = 5 and BC = 12 whats the area of the shaded portion to t      Log On


   

Question 478967: in the diagram, right triangle ABC is inscribed in circle O, angle ACB is a right angle, line segment AB is a diameter, AC = 5 and BC = 12 whats the area of the shaded portion to the nearest tenth
Answer by cleomenius(959) About Me  (Show Source):
You can put this solution on YOUR website!
I can't see the diagram, I am assuming you want the are of the circle which does not contain the triangle.
So, we have a right triangle with legs 5 and 12, by a^2 + b^2 = c^2 we get the hypotenuse to be 13.
This is also the diameter of the circle as given.
We can find the area of the triangle to be 1/2 5 * 12 = 30.
We can find the area of the circle as pi (6.5)^2 = 42.25 * pi = 132.73.
132.73 - 30 = 102.73., the area of the circle which is not contained in the triangle.
Cleomenius.