SOLUTION: What are the dimensions, in feet, of a rectangular sign whose area is 55 square feet, whose length is given by x + 8, and whose width is given by x + 2?

Algebra ->  Rectangles -> SOLUTION: What are the dimensions, in feet, of a rectangular sign whose area is 55 square feet, whose length is given by x + 8, and whose width is given by x + 2?      Log On


   



Question 478929: What are the dimensions, in feet, of a rectangular sign whose area is 55 square feet, whose length is given by x + 8, and whose width is given by x + 2?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the formula for the area of a rectangle of length L and width W:
A+=+L%2AW Substitute A+=+55, L+=+x%2B8, and W+=+x%2B2 to get:
55+=+%28x%2B8%29%28x%2B2%29 Simplify.
55+=+x%5E2%2B10x%2B16 Subtract 55 from both sides.
x%5E2%2B10x-39+=+0 Factor.
x-3%29%28x%2B13%29+=+0 Apply the "zero product" rule.
x-3+=+0 or x%2B13+=+0 so...
x+=+3 or x+=+-13 Discard the negative solution as length and width are positive values.
x+=+3
L+=+x%2B8 Substitute x+=+3
highlight%28L+=+11%29
W+=+x%2B2 Substitute x+=+3
highlight%28W+=+5%29