SOLUTION: Factor sin8Θ + 2sin4Θcos4Θ + cos8Θ? Verify (cos2Θ + sin2Θ)/(cosΘ) = secΘ?

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Question 478827: Factor sin8Θ + 2sin4Θcos4Θ + cos8Θ?
Verify (cos2Θ + sin2Θ)/(cosΘ) = secΘ?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If those are exponents:
Sub x for sine and y for cosine:
x%5E8+%2B+2xy+%2B+y%5E8
Can you do it now?
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(cos^2 + sin^2)/cos = sec
1/cos = sec
I'm convinced.