SOLUTION: okay, so I need help with these 3 problems. 1.) 2ab over 6a = a. 3 over b b. 1 over 3b c. b over 3 d. 3 over ab e. a over b 2.) if y = 1 over 4, then 15 over y = a.1 over

Algebra ->  Test -> SOLUTION: okay, so I need help with these 3 problems. 1.) 2ab over 6a = a. 3 over b b. 1 over 3b c. b over 3 d. 3 over ab e. a over b 2.) if y = 1 over 4, then 15 over y = a.1 over      Log On


   

Question 478613: okay, so I need help with these 3 problems.
1.) 2ab over 6a =
a. 3 over b
b. 1 over 3b
c. b over 3
d. 3 over ab
e. a over b
2.) if y = 1 over 4, then 15 over y =
a.1 over 60
b.1 over 5
c.5
d.60
e.30
3.) the price of a jacket was increased from $140 to $168. What was the percent increase in the price of the jacket?
a.10%
b.20%
c.30%
d.40%
e.16.7%

thanks so much for your help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

2ab/6a = b/3



y = 1/4, then 15/y = 15+%2F%281%2F4%29 = 60



price of a jacket was increased from $140 to $168: marked up $28

  28/140 = .20  OR 20% increase