SOLUTION: Hi can someone help show me how this equation will look when graphed? "sketch the following graph" {{{x^2/16 -y^2/4 = 1}}}

Algebra ->  Graphs -> SOLUTION: Hi can someone help show me how this equation will look when graphed? "sketch the following graph" {{{x^2/16 -y^2/4 = 1}}}      Log On


   

Question 47857: Hi can someone help show me how this equation will look when graphed?
"sketch the following graph"
x%5E2%2F16+-y%5E2%2F4+=+1
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
This will look like a hyperbola.
Standard Form: %28x+-+h%29%5E2%2Fa%5E2+-+%28y+-+k%29%5E2%2Fb%5E2+=+1
Centre(h,k)
C(0,0)
a = 4
b = 2
This hyperbola is horizontal because the x value is over the a value.
Asymptote: y+-+y1+=+M%28x+-+x1%29 where M = +-b%2Fa
Asymptote: y = +-%281%2F2%29x

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x^2/16 -y^2/4 = 1
The graph is a hyperbola with its center at (0,0)
intersecting the x-axis at (4,0) and (-4,0). It
opens to the right and to the left.
Cheers,
Stan H.