SOLUTION: how do you find the vertex, axis of symmetry, and direction of the opening of the parabola 1. y^2=-8x 2. (y-8)^2=-4(x-4)

Algebra ->  Rational-functions -> SOLUTION: how do you find the vertex, axis of symmetry, and direction of the opening of the parabola 1. y^2=-8x 2. (y-8)^2=-4(x-4)      Log On


   

Question 478267: how do you find the vertex, axis of symmetry, and direction of the opening of the parabola
1. y^2=-8x
2. (y-8)^2=-4(x-4)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

find the vertex, axis of symmetry, and direction of the opening of the parabola 

Putting into vertex form

the vertex form of a parabola opening right or left, x=a%28y-k%29%5E2+%2Bh where(h,k) is the vertex.

1. y^2=-8x 

  (-1/8)y^2 = x   Vertex (0,0), a = (-1/8)<0 opens to the left along x-axis

2. (y-8)^2=-4(x-4)

 (1/4)(y-8)^2 +4 = x  Vertex(4,8) a = (-1/4) opens left along y = 8