SOLUTION: Can you please tell me if the answer to this question that I got is correct? (-10xy^3z^2)^3= x^3y^9z^6/1000, just to clarify, x to the third, y to the ninth, z to the sixth over 1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can you please tell me if the answer to this question that I got is correct? (-10xy^3z^2)^3= x^3y^9z^6/1000, just to clarify, x to the third, y to the ninth, z to the sixth over 1      Log On


   



Question 47801: Can you please tell me if the answer to this question that I got is correct?
(-10xy^3z^2)^3= x^3y^9z^6/1000, just to clarify, x to the third, y to the ninth, z to the sixth over 1000 Thank you so much for the help!!!

Found 2 solutions by consc198, ikleyn:
Answer by consc198(59) About Me  (Show Source):
You can put this solution on YOUR website!
Yes that is correct!!

Answer by ikleyn(53875) About Me  (Show Source):
You can put this solution on YOUR website!
.
Can you please tell me if the answer to this question that I got is correct?
(-10xy^3z^2)^3= x^3y^9z^6/1000, just to clarify, x to the third, y to the ninth, z to the sixth over 1000
Thank you so much for the help!!!
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From @consc198, you got the answer "Yes that is correct !".

This answer is TOTALLY WRONG !

The answer you got is WRONG.

The correct identity is

(-10xy^3z^2)^3= -1000*x^3*y^9*z^6.


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Keep in mind that this "enthusiast" @consc198 is practically illiterate in Math.

Looking in his output at this forum, I see that he produced 58 posts/solutions,
and then suddenly stopped his activity.

I hope that the managers of the other site, where he was affiliated, got understanding
that his qualification in Math is below any acceptable level and removed him from the staff.