SOLUTION: Find four consecutive even integers such that the sum of the first and second is 70 less than the product of the third and the fourth.

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Question 477997: Find four consecutive even integers such that the sum of the first and second is 70 less than the product of the third and the fourth.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be
x,x+2,x+4,x+6
x+x+2= (x+4)(x+6)-70
2x+2=x^2+10x+24-70
x^2+10x-2x+24-70-2=0
x^2+8x-48=0
x^2+12x-4x-48=0
x(x+12)-4(x+12)=0
(x+12)(x-4)=0
x=-12 OR x=4
-12,-10,-8,-6
OR
4,6,8,10