SOLUTION: Of 15 windup toys on a sale table, 4 are defective. If 2 toys are selected at random, find the expected number of defective toys.
Please include step and step:)
THANKS!!
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-> SOLUTION: Of 15 windup toys on a sale table, 4 are defective. If 2 toys are selected at random, find the expected number of defective toys.
Please include step and step:)
THANKS!!
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Question 477883: Of 15 windup toys on a sale table, 4 are defective. If 2 toys are selected at random, find the expected number of defective toys.
Please include step and step:)
THANKS!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Of 15 windup toys on a sale table, 4 are defective. If 2 toys are selected at random, find the expected number of defective toys.
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Random number of defective toys: 0:::::::::1:::::::::::::::::2
Corresponding Probabilities::(11/15)^2::2*(4/15)(11/15)::(4/15)^2
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E(x) = 0 + 1[2(44/225)] + 2[16/225] = (88+32)/225 = 120/225 = 24/45
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Cheers,
Stan H.
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