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Question 477604: 1.The equation of the parabola whose focus is at (-3, 0) and directrix x = 3 is:
2.The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:
3.The equation of the parabola whose focus is at (7, 0) and directrix at x = -7 is:
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! 1.The equation of the parabola whose focus is at (-3, 0) and directrix x = 3 is:
2.The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:
3.The equation of the parabola whose focus is at (7, 0) and directrix at x = -7 is:
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1. Parabola opens leftwards.
Axis of symmetry: y=0 or x-axis
Vertex=(0,0)
p=distance from vertex to focus or to directrix on the axis of symmetry=3
Equation:
y^2=-4px
y^2=-12x
..
2. Parabola open upwards.
Axis of symmetry: x=0 or y-axis
Vertex=(0,0)
p=distance from vertex to focus or to directrix on the axis of symmetry=5
Equation:
x^2=4py
x^2=20y
..
3.Parabola opens rightwards.
Axis of symmetry: y=0 or x-axis
Vertex=(0,0)
p=distance from vertex to focus or to directrix on the axis of symmetry=7
Equation:
y^2=4px
y^2=28x
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