SOLUTION: Joe has a collection of nickles and dimes worth $6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be $8.85. How

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Joe has a collection of nickles and dimes worth $6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be $8.85. How       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 477578: Joe has a collection of nickles and dimes worth $6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be $8.85. How many nickles and dimes does he have?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Let x and y represent the number of nickels and dimes respectively

Question states***CENTS makes sense

  5x + 10y = 620

5(x-7) + 10(2y) = 885



  5x + 10y = 620

  5x + 10(2y) = 920



  -5x - 10y = -620

   5x + 10(2y) = 920

           10y = 300

             y = 30, the number of dimes. Number of nickels is 64.



CHECKING our Answer***

5(x-7) + 10(2y) = 885

5*57 + 10*60 = 285 + 600 = 885 OR $8.85