SOLUTION: Solve the following logarithmic equations showing all work. ln 7 + ln (n - 2) = ln 6n log516 - log52t = log52 log5m = log5125 logy = log16 + log49 log6(b2 + 2) + l

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve the following logarithmic equations showing all work. ln 7 + ln (n - 2) = ln 6n log516 - log52t = log52 log5m = log5125 logy = log16 + log49 log6(b2 + 2) + l      Log On


   

Question 477565: Solve the following logarithmic equations showing all work.
ln 7 + ln (n - 2) = ln 6n
log516 - log52t = log52
log5m = log5125
logy = log16 + log49
log6(b2 + 2) + log62 = 2
log3(5x+5) - log3(x2 - 1) = 0
log2(x - 2) + 5 = 8 - log2 4
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following logarithmic equations showing all work.
ln 7 + ln (n - 2) = ln 6n
Adding logs --> multiplying
ln(7) + ln(n-2) = ln(6n)
ln(7(n-2)) = ln(6n)
If the logs are equal,
7(n-2) = 6n
7n-14 = 6n
n = 14
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log516 - log52t = log52
log(516) = log(52t) + log(52)
similar to the 1st one.
------------------
log5m = log5125
See #1
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logy = log16 + log49
See #1
-----------
log6(b2 + 2) + log62 = 2
Is 6 the base? Not clear
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log3(5x+5) - log3(x2 - 1) = 0
If 3 is the base, then
log%283%2C5x%2B5%29+=+log%283%2C%28x%5E2+-+1%29%29
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log2(x - 2) + 5 = 8 - log2 4
If 2 is the base,
log%282%2C%28x-2%29%29+=+3+-+log%282%2C4%29+=+3+-+2+=+1
x- 2 = 2
x = 4