102002 is divisible by 4, 5 and 101001 but 2
isn't divisible by any of those, so A, B and E are ruled out.
102002 + 2 is certainly divisible by 2, because
both terms are even.
If you subtract 1 from any positive integer power of 10,
you will always get a string of 9's.
Example:
100000000000000000
-1
------------------
99999999999999999
102002 + 2 = (102002 - 1) + 3 = [a string of 2002 9's] + 3.
That is divisible by 3 because any string of 9's is divisible by 3.
So 10^2002 + 2 is divisible by 6 since it's divisible by both 2 and 3.
So C is a correct answer. But we should rule out D:
Any string of 9's is divisible by 9 but 3 isn't, so D is ruled out.
Answer: C 6
Edwin
