SOLUTION: Find three consecutive odd whole numbers such that the sum of the squares of the two smaller numners is 9 more than the square of the largest.
Question 477301: Find three consecutive odd whole numbers such that the sum of the squares of the two smaller numners is 9 more than the square of the largest. Answer by robertb(5830) (Show Source):
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<==> (x - 7 )(x + 3 ) = 0 ==> x = 7, -3.
Eliminate -3 because it is not non-negative.
==> the numbers are 7,9, 11.
