Question 477280: Two cars travel the same route, both leaving from the same point. The slower car averages 40 mph, and the faster car 50 mph. If the faster car leaves 2 hours later than the slower one, in how many hours, will the faster car catch up to the slower one?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Two cars travel the same route, both leaving from the same point. The slower car averages 40 mph, and the faster car 50 mph. If the faster car leaves 2 hours later than the slower one, in how many hours, will the faster car catch up to the slower one?
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Slower Car DATA:
rate = 40 mph ; time = x hrs ; distance = 40x miles
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Faster Car DATA:
rate = 50 mph ; time = x-2 hrs ; distance = 50(x-2)
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Equation:
distance = distance
40x = 50(x-2)
40x = 50x - 100
10x = 100
x = 10 hrs
x-2 = 8 hrs (time for the faster car to catch the slower car)
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cheers,
Stan H.
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