Question 477152: Determine the value of r so that the line through (6,r) and (9,2) is perpendicular to 5x-3y-9. Please help, I don't know how to do this at all. Thanks in advance.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Determine the value of r so that the line through (6,r) and (9,2) is perpendicular to 5x-3y-9.
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assuming given equation is correctly written as follows:
5x-3y=9
rewrite in standard form for a straight line: y=mx+b, m=slope, b= y-intercept
3y=5x-9
y=5x/3-3
slope,m,=5/3
..
Slope of line perpendicular to given equation and passing thru (6,r) and (9,2)
=-1/m=-3/5=∆y/∆x=(2-r)/(9-6)
-3/5=(2-r)/3
-9=10-5r
5r=10+9=19
r=19/5
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