Question 477140: The area of a regular octagon is 35 sq. cm. What is the area of a regular octagon with sides six times as large?
Answer by jorel1380(3719)   (Show Source):
You can put this solution on YOUR website! For a regular octagon, A = 2(1+ sqrt2)xS^2 = 4.828 S^2.
Since the area varies as the square of the sides, an increase by a factor of 6 for the sides will result in an increase of 6^2, or 36 times the original size. Is there going to be any ultimate fighting in this octagon?
|
|
|
