SOLUTION: Given the function {{{ f(x)=2x^2+3x-5 }}} evaluate f(3). I did: {{{ f(x)=2(3)^2+3 }}} =54+3 =57 so f(x)=57? Did I do that right?

Algebra ->  Functions -> SOLUTION: Given the function {{{ f(x)=2x^2+3x-5 }}} evaluate f(3). I did: {{{ f(x)=2(3)^2+3 }}} =54+3 =57 so f(x)=57? Did I do that right?       Log On


   

Question 477133: Given the function +f%28x%29=2x%5E2%2B3x-5+ evaluate f(3). I did:
+f%28x%29=2%283%29%5E2%2B3+
=54+3
=57
so f(x)=57? Did I do that right?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 2x^2+3x-5 evaluate f(3)
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f(3) = 2*3^2 + 3*3 - 5
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f(3) = 18 + 9 - 4
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f(3) = 23
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Cheers,
Stan H.
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