SOLUTION: At Maplewood Marine, shift 1 produced 3 times as much as shift 2. Maplewood's total production for June was 6,400 row boats. What was the output for each shift?
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Question 4771: At Maplewood Marine, shift 1 produced 3 times as much as shift 2. Maplewood's total production for June was 6,400 row boats. What was the output for each shift? Answer by ichudov(507) (Show Source):
You can put this solution on YOUR website! The problem says that shift one production is 3 times shift two.
shift_one_production+shift_two_production=6400
since shift_one_production = 3* shift_two_production, we have
3* shift_two_production + shift_two_production = 6400
4*shift_two_production = 6400.
shift_two_production = 6400/4 = 1600
shift_one_production = 1600*3 = 4800.
You could have used 'x' instead of shift_one_production, the result would be the same.
