SOLUTION: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 13% protein ?
Question 477048: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 13% protein ? Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 13% protein ?
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Equation:
protein + protein = protein
0.16s + 0.08(320-s) = 0.13*320
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Multiply thru by 100 to get:
16s + 8*320 - 8s = 13*320
8s = 5*320
s = 5*40
Amount of soybean meal needed is 200 lb
Amount of cornmeal needed is 120 lb
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Cheers,
Stan H.
You can put this solution on YOUR website! Let = pounds of soybean meal needed
Let = pounds of cornmeal needed
In words:
(total pounds of protein in final mixture) / (total pounds in final mixture) = 13%
given: = pounds of protein in soybean meal = pounds of protein in cornmeal
(1)
(2)
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Multiply both sides of (2) by
(2)
Multiply both sides by
(2)
Divide both sides by
(2)
Subtract (1) from (2)
(2)
(1)
and, since
(1)
(1)
(1)
200 pounds of soybean meal and 120 pounds
of cornmeal need to be mixed
check answer:
(2)
(2)
(2)
(2)
(2)
OK
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