SOLUTION: The length of a rectangular garden is 3 ft less than 2 times its width. If the perimeter of the garden is 54 ft, find the dimensions of the garden.

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Question 47683This question is from textbook Beginning Algebra
: The length of a rectangular garden is 3 ft less than 2 times its width. If the perimeter of the garden is 54 ft, find the dimensions of the garden. This question is from textbook Beginning Algebra

Found 2 solutions by Nate, checkley71:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 2w - 3
2w+%2B+2l+=+Perimeter
2w+%2B+4w+-+6+=+54
6w+=+60
w+=+10
length = 2w - 3 = 20 - 3 = 17
17ft x 10ft

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LENGTH =2W-3 & WIDTH =W THE L*W=54 OR (2W-3)W=54 OR 2W~2-3W-54=0 OR
(W-6)(W+4.5)=0 OR W=6 & W=-4.5
PROOF (12-3)6=54 OR 9*6=54 OR 54=54