SOLUTION: Problem:
The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality repr
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The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality repr
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Question 47680This question is from textbook Beginning Algebra
: Problem:
The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality representing the number of minutes a person could talk without exceeding $3.00
This is what I have so far and I am stuck.
A _<_ 300 cents($3)
This is for the first minute 0.036+B<300
LET x be the number of minutes , each minute will cost 0.21 cents
so the B is 0.21X
0.036 + 0.21X<300.......1
But x I know cannot be a negative so I do not know what to do.
Please advise.
I hope what I wrote makes sense I could not get my equation editor to paste thesign with a line on it. This question is from textbook Beginning Algebra
You can put this solution on YOUR website! The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality representing the number of minutes a person could talk without exceeding $3.00
Let "x" be the number of minutes a person talks.
Cost= 0.36 + (x-1)0.21
If you want the cost to be <=$3.00 you have the following:
0.36 +(x-1)0.21<=3
Multiply thru by 100 to get rid of the decimals, as follows:
36 + (x-1)(21)<=300
(x-1)<=12.57
x<=13.57 minutes
Cheers,
Stan H.
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